Answer :
Final answer:
Approximately 3.192 × 10²24 aluminum atoms are present in 143 grams of aluminum, calculated using the atomic mass of aluminum and Avogadro's number.
Explanation:
To calculate the number of atoms in 143 grams of aluminum, we can use the concept of moles and Avogadro's number. The atomic mass of aluminum is 26.98 g/mol, which means that one mole of aluminum has a mass of 26.98 grams and contains 6.022 × 1023 atoms (Avogadro's number).
First, we calculate the number of moles of aluminum in 143 grams:
(143 g Al) × (1 mol Al / 26.98 g Al) = 5.300 moles of Al
Then, we use Avogadro's number to find the number of atoms:
5.300 moles × 6.022 × 1023 atoms/mol = 3.192 × 1024 aluminum atoms
Therefore, there are approximately 3.192 × 1024 aluminum atoms in 143 grams of aluminum.
