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------------------------------------------------ How high could the water shoot if it came vertically out of a broken pipe in front of the house? The pressure is constant throughout and equal to $1.01 \times 10^5$ Pa.

A. 1055 m
B. 92.5 m
C. None of the given options
D. 98.3 m
E. 87.3 m

The height that water could reach when shooting out of a broken pipe with a pressure of 1.01 imes 10^5 Pa is approximately 10.3 meters, which means the correct answer is 'None of the given options'. Therefore the correct answer is C

Explanation:

The question asks how high water could shoot if it came out of a broken pipe with a pressure of 1.01 imes 10^5 Pa. To solve for the maximum height (h) that the water could reach, we can use the equation derived from Bernoulli's principle which relates pressure (P), the density of the fluid (
h o), gravitational acceleration (g), and height (h). The equation is P =
h o gh.

By rearranging the equation to solve for h, we get:

h = rac{P}{
h o g}

Assuming that the density of water is 1000 kg/m^3 and the acceleration due to gravity is 9.81 m/s^2, we can plug in the numbers:

h = rac{1.01 imes 10^5 Pa}{1000 kg/m^3 imes 9.81 m/s^2}

h = rac{1.01 imes 10^5}{9810}

h = 10.3 m