(HELP ME PLS, 10TH GRADE GEOMETRY) Two parallel lines are crossed by a transversal.
If m1 = 61.8°, then m6 is ... ?
A.61.8
B.81.8
C.98.2
D.118.2

we know that
m∠1+m∠2=[tex]180\°[/tex] -------> by supplementary angles
we have
m∠1=[tex]61.8\°[/tex]
substitute
m∠2=[tex]180\°-61.8\°=118.2\°[/tex]
m∠6=m∠2 -------> by corresponding angles
so
m∠6=[tex]118.2\°[/tex]
therefore
the answer is the option D
[tex]118.2\°[/tex]