Half-life Problems

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1. The half-life of cesium-137 is 30.2 years. If the initial mass of a sample of cesium-137 is 1.00 kg, how much (in kilograms) will remain after 151 years?

Answer :

Final answer:

To find the mass of cesium-137 remaining after 151 years, we can use the formula for exponential decay and solve for A. Plugging in the values, we find that approximately 0.104 kg (or 104 grams) will remain.


Explanation:

To solve this problem, we can use the formula for exponential decay: A = A0(1/2)t/h, where A is the final amount, A0 is the initial amount, t is the time elapsed, and h is the half-life. In this case, the initial mass is 1.00 kg, the time elapsed is 151 years, and the half-life is 30.2 years. Plugging these values into the formula, we have:

A = 1.00 kg * (1/2)^(151/30.2)

Simplifying this calculation, we find that approximately 0.104 kg (or 104 grams) of cesium-137 will remain after 151 years.


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