High School

Gold has a specific heat of 126 J/(kg·K). A sculptor increased the temperature of a 0.5 kg block of gold by 10°C. How much energy did the sculptor add to the gold?

Answer :

Answer:

630 J

Explanation
:

The formula for the heat required is

q = mCΔT

q = 0.5 × 126 × 10

q = 630 J

Energy Change= Mass X Specific Heat X Temperature Change

126 times .5 = 63.

63 times 10= 630

630 joules

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