Answer :
Final answer:
The magnitude of vector A is approximately 9.85 m and the magnitude of vector B is approximately 7.48 m.
Explanation:
To find the magnitudes of the given vectors A and B, we can use the formula:
|V| = sqrt(Vx^2 + Vy^2 + Vz^2)
For vector A = (6.00 î – 6.00 ĵ + 5.00 k) m:
Vx = 6.00, Vy = -6.00, Vz = 5.00
|A| = sqrt((6.00)^2 + (-6.00)^2 + (5.00)^2)
|A| = sqrt(36.00 + 36.00 + 25.00)
|A| = sqrt(97.00)
|A| ≈ 9.85 m
For vector B = (4.00 î + 6.00 ĵ – 2.00 h) m:
Vx = 4.00, Vy = 6.00, Vz = -2.00
|B| = sqrt((4.00)^2 + (6.00)^2 + (-2.00)^2)
|B| = sqrt(16.00 + 36.00 + 4.00)
|B| = sqrt(56.00)
|B| ≈ 7.48 m
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