High School

$\frac{8}{12} \times \frac{25}{141} = ?\n\n1. \frac{60}{25}\n2. \frac{115}{141}\n3. \frac{7}{12}\n4. \frac{25}{141}$

Answer :

To solve the problem [tex]\frac{8}{12} \times \frac{25}{141}[/tex], we perform the following steps:

  1. Multiply the Numerators:

    • Multiply the top numbers of each fraction: [tex]8 \times 25 = 200[/tex].
  2. Multiply the Denominators:

    • Multiply the bottom numbers of each fraction: [tex]12 \times 141 = 1692[/tex].
  3. Form the New Fraction:

    • Combine the results to form a new fraction: [tex]\frac{200}{1692}[/tex].
  4. Simplify the Fraction:

    • First, identify a common factor that divides both the numerator and the denominator.
    • The greatest common divisor (GCD) of 200 and 1692 is 4.
    • Divide both numerator and denominator by their GCD:
      [tex]\frac{200 \div 4}{1692 \div 4} = \frac{50}{423}[/tex]

The simplified answer for the multiplication [tex]\frac{8}{12} \times \frac{25}{141}[/tex] is [tex]\frac{50}{423}[/tex].

None of the options listed match [tex]\frac{50}{423}[/tex]. It seems there may not be a correct option provided based on the multiplication and simplification of the fractions.