Answer :
To find the current through the battery when four 15.6-ohm resistors are connected in parallel across a 19.7 V battery, first calculate the total resistance in parallel and then apply Ohm's law. The total resistance is 3.9 ohms, resulting in a current of 5.05 amperes.
The question is asking about the amount of current through the battery when four 15.6-ohm resistors are connected in parallel across a 19.7 V battery. To solve this, we can use Ohm's law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R). First, we calculate the total resistance for resistors in parallel, which is the reciprocal of the sum of the reciprocals of the individual resistances.
Total resistance for parallel resistors: 1/Rtotal = 1/R1 + 1/R2 + 1/R3 + 1/R4. In this case, all resistors have the same value, so the calculation simplifies to 1/Rtotal = 4/R, where R is 15.6 ohms. Thus, total resistance Rtotal = 15.6 ohms / 4 = 3.9 ohms.
Then, we can find the total current using Ohm's law: I = V / Rtotal. Substituting the known values, we get: I = 19.7 V / 3.9 ohms, which results in a current of 5.05 amperes.
