High School

For questions 2-3, use partial quotients to divide.

2. How many 4s are in 6,787?
[tex]6,787 \div 4[/tex]

3. How many 5s are in 6,209?
[tex]6,209 \div 5[/tex]

Answer :

Sure! Let's solve the division problems step-by-step using partial quotients.

1. How many 4s are in 6,787 (6,787 ÷ 4)?

To tackle this problem using partial quotients, you break down the division into simpler, manageable parts:

- Start by estimating how many 4s fit into 6,787. A good approach is to think in terms of large, rounded numbers.

- First, try 1,000 times 4, which is 4,000. Subtract this from 6,787:
- 6,787 - 4,000 = 2,787

- Next, think of another large number. Try 500 times 4, which is 2,000. Subtract this from 2,787:
- 2,787 - 2,000 = 787

- Then try 100 times 4, resulting in 400. Subtract it:
- 787 - 400 = 387

- Try 90 times 4, which is 360. Subtract it:
- 387 - 360 = 27

- Finally, 6 times 4 is 24. Subtract this:
- 27 - 24 = 3

- The remainder is 3, which cannot be divided further by 4. Add all the partial quotients together:
- 1,000 + 500 + 100 + 90 + 6 = 1,696

Therefore, 4 goes into 6,787 a total of 1,696 times with a remainder of 3.

2. How many 5s are in 6,209 (6,209 ÷ 5)?

For this, we also use partial quotients:

- Estimate how many 5s fit into 6,209:

- Start with 1,000 times 5, which is 5,000. Subtract it from 6,209:
- 6,209 - 5,000 = 1,209

- Try 200 times 5, which is 1,000. Subtract:
- 1,209 - 1,000 = 209

- Next, 40 times 5 equals 200. Subtract this:
- 209 - 200 = 9

- 1 time 5 is 5. Subtract:
- 9 - 5 = 4

- The remainder is 4, which cannot be divided further by 5. Add all the partial quotients together:
- 1,000 + 200 + 40 + 1 = 1,241

Therefore, 5 goes into 6,209 a total of 1,241 times with a remainder of 4.

These are the results for the divisions: There are 1,696 times 4 in 6,787, and there are 1,241 times 5 in 6,209.