Answer :
The probability that at least one missile will fire is 1 because the probability that none of the missiles will fire is 0. Therefore, the answer is (d) 30/30.
The complement of "at least 1 missile will fire" is "none of the missiles will fire." So we can find the probability of this happening, and then subtract it from 1 to get the probability that at least 1 missile will fire.
The probability that the first missile selected will not fire is 3/10.
Since the missile is not replaced after being fired, the probability that the second missile selected will not fire is 2/9 (since there are only 9 missiles left in the lot).
Similarly, the probability that the third missile selected will not fire is 1/8.
Finally, the probability that the fourth missile selected will not fire is 0/7 (since there is only 1 missile left in the lot).
Therefore, the probability that none of the missiles will fire is:
(3/10) * (2/9) * (1/8) * (0/7) = 0
So the probability that at least 1 missile will fire is:
1 - 0 = 1
Therefore, the answer is (d) 30/30.
To practice more questions about probability:
https://brainly.com/question/24756209
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