Answer :
Final answer:
To convert the equivalent of 8mEq lithium to an equivalent mass of Lithium Carbonate (Li₂CO₃), i.e., for each 5mL dose of syrup, we calculate the amount of lithium first and then convert it to lithium carbonate. The equivalent in each 5mL dose of syrup is around (B) 296 mg of Lithium Carbonate (Li₂CO₃).
Explanation:
In order to calculate the equivalent of Lithium Carbonate (Li₂CO₃) in a 5ml dose of syrup which contains 8 mEq of Li⁺, we need a step-by-step calculation to approach the answer.
Firstly, 1 mole of Lithium (Li+) is equal to 6.94 grams and 1 Eq or mEq is 1/1000 of a mole. So, 8 mEq of Li+ are equal to 0.05552 grams or 55.52 milligrams of lithium.
Secondly, in Lithium Carbonate (Li₂CO₃), the proportion of lithium is 2 * 6.94g / 73.89g = 0.188 or 18.8%. Therefore, the amount of Lithium Carbonate is 55.52mg / 0.188 = 295.53mg.
So, each 5mL dose of syrup contains the equivalent of approximately 296 mg of Lithium Carbonate (Li₂CO₃).
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