Answer :
Final answer:
The resistance of a 2-meter long wire with a cross-sectional area of 1.55 x 10^-6 m² and a resistivity of 2.8 x 10^-8 ohm meters is 36.1 ohms.
Explanation:
To find the resistance of a wire given its length, cross-sectional area, and resistivity, we can use the formula:
R = h(L/A)
where:
R is the resistance in ohms ( Ω).
h (rho) is the resistivity of the material in ohm meters ( Ω·m).
L is the length of the wire in meters (m).
A is the cross-sectional area of the wire in square meters (m²).
For this question, let's plug in the values:
R = 2.8 x 10-8 Ω·m * 2 m / 1.55 x 10-6 m²
R = 2.8 x 10-8 Ω·m * 1.29 x 106 1/m²
R = 36.12 Ω
The resistance of the wire is 36.1 ohms (rounded to one decimal place).
