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------------------------------------------------ Find the resistance of a wire that is 2 m long, with an area of [tex]1.55 \times 10^{-6} \, \text{m}^2[/tex], and a resistivity of [tex]2.8 \times 10^{-8} \, \text{ohm meter}[/tex].

Question

High School

Answer :

ayanqureshi21 ayanqureshi21 · Answer 1 · 2024-10-21T18:46:32-04:00

The resistance of a 2-meter long wire with a cross-sectional area of 1.55 x 10^-6 m² and a resistivity of 2.8 x 10^-8 ohm meters is 36.1 ohms.

To find the resistance of a wire given its length, cross-sectional area, and resistivity, we can use the formula:

R = h(L/A)

where:

R is the resistance in ohms ( Ω).

h (rho) is the resistivity of the material in ohm meters ( Ω·m).

L is the length of the wire in meters (m).

A is the cross-sectional area of the wire in square meters (m²).

For this question, let's plug in the values:

R = 2.8 x 10-8 Ω·m * 2 m / 1.55 x 10-6 m²

R = 2.8 x 10-8 Ω·m * 1.29 x 106 1/m²

R = 36.12 Ω

The resistance of the wire is 36.1 ohms (rounded to one decimal place).