College

Find the general solution to the exact differential equation:

[tex]
\frac{d y}{d x} = \csc^2 x - 12 x^5
[/tex]

A. [tex] y = -\cot x \csc x - 2x^6 + C [/tex]

B. [tex] y = -\cot x - 12x^6 + C [/tex]

C. [tex] y = -\cot x - 2x^6 + C [/tex]

D. [tex] y = \cot x - 2x^6 + C [/tex]

Answer :

To find the general solution to the differential equation [tex]\(\frac{d y}{d x} = \csc^2 x - 12 x^5\)[/tex], we need to integrate each term separately. Let's go through the steps:

1. Identify the Differential Equation:
We have [tex]\(\frac{d y}{d x} = \csc^2 x - 12 x^5\)[/tex].

2. Separate the Terms:
We can rewrite this as:
[tex]\[
\frac{d y}{d x} = \csc^2 x - 12 x^5
\][/tex]
Our task is to integrate each part with respect to [tex]\(x\)[/tex].

3. Integrate [tex]\(\csc^2 x\)[/tex]:
The integral of [tex]\(\csc^2 x\)[/tex] with respect to [tex]\(x\)[/tex] is known to be [tex]\(-\cot x\)[/tex]. This is a standard trigonometric integral.

4. Integrate [tex]\(-12 x^5\)[/tex]:
The integral of [tex]\(-12 x^5\)[/tex] with respect to [tex]\(x\)[/tex] is calculated by finding the antiderivative:
[tex]\[
\int -12 x^5 \, dx = -2 x^6
\][/tex]
This is done by increasing the exponent by one (to 6) and dividing by the new exponent.

5. Combine the Results:
After integrating both terms, we combine them to get the general solution of the differential equation:
[tex]\[
y = -\cot x - 2 x^6 + C
\][/tex]
where [tex]\(C\)[/tex] is an arbitrary constant representing the constant of integration.

Thus, the general solution to the differential equation is:
[tex]\[
y = -\cot x - 2 x^6 + C
\][/tex]