Middle School

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ Find the error in the work below. Then show the correct calculation.

Given Calculation:
\[ \frac{8}{12} \times 6 = 8 \times \frac{1}{12} \times 6 = 8 \times \frac{1}{72} = \frac{8}{72} = \frac{1}{9} \]

Correct Calculation:
\[ \frac{8}{12} \times 6 = \frac{8 \times 6}{12} = \frac{48}{12} = 4 \]

Answer :

Final answer:

The error was in the handling of the multiplication and division in the expression 8/12 x 6. The proper calculation should simplify the fraction before multiplying, leading to the correct answer of 4.

Explanation:

To find the error in the mathematical operation 8/12 x 6, let us examine each step that was provided:

The original equation was manipulated incorrectly; the mistake lies in the manipulation of the division and multiplication steps. The student incorrectly changed the operation into 8 x 1/12 x 6, which then led to 8 x 1/72 and finally an incorrect simplification to 8/72, which they further reduced to 1/9. However, the correct approach is to either simplify the fraction first or perform the multiplication as shown:

  1. Simplify 8/12 by dividing both the numerator and denominator by their greatest common divisor, which is 4. This gives us 2/3.
  2. Multiply the resulting fraction by 6: 2/3 x 6.
  3. Since 6 is equivalent to 6/1, we multiply the numerators together (2 x 6) and the denominators together (3 x 1), resulting in 12/3.
  4. Finally, we simplify 12/3 to get the answer: 4.

The correct calculation is therefore 8/12 x 6 = 2/3 x 6 = 4.
  • The calculation is as follows;

Here we have to use BODMAS

(Bracket, Of, Division, Multiplication, Addition and Subtraction).

Like

We can re- write it as

[tex]= (8\div 12) \times 6\\\\= (2\div 3) \times 6\\\\= (2) \times 2[/tex]

= 4

Learn more: https://brainly.com/question/864553?referrer=searchResults

Other Questions