Answer :
To solve the question of finding [tex]\( f(\ln \frac{1}{z}) \)[/tex] under the condition that [tex]\(\ln f = 17.006\)[/tex], let's follow the steps:
1. Understanding the Given:
- We have [tex]\(\ln f = 17.006\)[/tex]. This means the natural logarithm of [tex]\( f \)[/tex] is 17.006.
2. Finding [tex]\( f \)[/tex]:
- To find [tex]\( f \)[/tex], we need to perform the exponential operation because the natural logarithm (ln) and the exponential function (e) are inverse functions. So, if [tex]\(\ln f = 17.006\)[/tex], then:
[tex]\[
f = e^{17.006}
\][/tex]
3. Calculate [tex]\( f \)[/tex]:
- Evaluating [tex]\( e^{17.006} \)[/tex] gives us approximately:
[tex]\[
f \approx 24300318.13013055
\][/tex]
This value of [tex]\( f \)[/tex] represents the frequency given the condition that [tex]\(\ln f = 17.006\)[/tex], which we calculated as around 24,300,318.13. Note that the question asked for [tex]\( f(\ln \frac{1}{z}) \)[/tex], but with the information provided, we focused on finding the value of [tex]\( f \)[/tex]. If further context or specific details about [tex]\( \ln \frac{1}{z} \)[/tex] are needed, those would depend on additional information about the variable [tex]\( z \)[/tex].
1. Understanding the Given:
- We have [tex]\(\ln f = 17.006\)[/tex]. This means the natural logarithm of [tex]\( f \)[/tex] is 17.006.
2. Finding [tex]\( f \)[/tex]:
- To find [tex]\( f \)[/tex], we need to perform the exponential operation because the natural logarithm (ln) and the exponential function (e) are inverse functions. So, if [tex]\(\ln f = 17.006\)[/tex], then:
[tex]\[
f = e^{17.006}
\][/tex]
3. Calculate [tex]\( f \)[/tex]:
- Evaluating [tex]\( e^{17.006} \)[/tex] gives us approximately:
[tex]\[
f \approx 24300318.13013055
\][/tex]
This value of [tex]\( f \)[/tex] represents the frequency given the condition that [tex]\(\ln f = 17.006\)[/tex], which we calculated as around 24,300,318.13. Note that the question asked for [tex]\( f(\ln \frac{1}{z}) \)[/tex], but with the information provided, we focused on finding the value of [tex]\( f \)[/tex]. If further context or specific details about [tex]\( \ln \frac{1}{z} \)[/tex] are needed, those would depend on additional information about the variable [tex]\( z \)[/tex].
