Answer :
Final answer:
To find the zeros of the equation x^5 - 3x^4 - 15x^3 + 45x^2 - 16x + 48 = 0, we need to factor the polynomial. By using polynomial long division or synthetic division, we can determine that x = -1 is a zero of the polynomial.
Explanation:
To find the zeros of the equation x^5 - 3x^4 - 15x^3 + 45x^2 - 16x + 48 = 0, we need to factor the polynomial.
By using polynomial long division or synthetic division, we can determine that x = -1 is a zero of the polynomial. Dividing the polynomial by (x + 1), we find a quotient of x^4 - 4x^3 - 11x^2 + 34x - 48.
Using a graphing calculator or factoring techniques, we can further factor the quartic polynomial and find the remaining zeros.
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