Answer :
Final answer:
To find the zeros of the cubic polynomial x^3 - 7x^2, we set f(x) = 0 and solve for x. The zeros are x = 0 and x = 7.
Explanation:
To find the zeros of the cubic polynomial f(x) = x^3 - 7x^3, we need to set f(x) = 0 and solve for x. So, x^3 - 7x^2 = 0. Factoring out x^2 gives us x^2(x-7) = 0. Setting each factor equal to zero, we find that the zeros are x = 0 and x = 7.
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