Answer :
Sure! Let's solve each part step by step:
(a) [tex]\(\frac{5}{6} = \frac{\square}{18}\)[/tex]
To find the missing number in this equivalent fraction, we'll use cross-multiplication. Cross-multiplication means multiplying across the equal sign diagonally:
[tex]\[5 \times 18 = 6 \times \text{(missing number)}\][/tex]
This simplifies to:
[tex]\[90 = 6 \times \text{(missing number)}\][/tex]
To solve for the missing number, divide both sides by 6:
[tex]\[\text{Missing number} = \frac{90}{6} = 15\][/tex]
So, [tex]\(\frac{5}{6} = \frac{15}{18}\)[/tex].
(b) [tex]\(\frac{2}{7} = \frac{10}{\square}\)[/tex]
Similarly, we'll use cross-multiplication here:
[tex]\[2 \times \text{(missing denominator)} = 7 \times 10\][/tex]
This simplifies to:
[tex]\[2 \times \text{(missing denominator)} = 70\][/tex]
To find the missing denominator, divide both sides by 2:
[tex]\[\text{Missing denominator} = \frac{70}{2} = 35\][/tex]
So, [tex]\(\frac{2}{7} = \frac{10}{35}\)[/tex].
(c) [tex]\(\frac{\square}{5} = \frac{32}{40}\)[/tex]
Again, use cross-multiplication:
[tex]\[\text{(missing numerator)} \times 40 = 5 \times 32\][/tex]
This simplifies to:
[tex]\[\text{(missing numerator)} \times 40 = 160\][/tex]
To find the missing numerator, divide both sides by 40:
[tex]\[\text{Missing numerator} = \frac{160}{40} = 4\][/tex]
So, [tex]\(\frac{4}{5} = \frac{32}{40}\)[/tex].
In summary:
- For part (a), the missing number is 15.
- For part (b), the missing denominator is 35.
- For part (c), the missing numerator is 4.
(a) [tex]\(\frac{5}{6} = \frac{\square}{18}\)[/tex]
To find the missing number in this equivalent fraction, we'll use cross-multiplication. Cross-multiplication means multiplying across the equal sign diagonally:
[tex]\[5 \times 18 = 6 \times \text{(missing number)}\][/tex]
This simplifies to:
[tex]\[90 = 6 \times \text{(missing number)}\][/tex]
To solve for the missing number, divide both sides by 6:
[tex]\[\text{Missing number} = \frac{90}{6} = 15\][/tex]
So, [tex]\(\frac{5}{6} = \frac{15}{18}\)[/tex].
(b) [tex]\(\frac{2}{7} = \frac{10}{\square}\)[/tex]
Similarly, we'll use cross-multiplication here:
[tex]\[2 \times \text{(missing denominator)} = 7 \times 10\][/tex]
This simplifies to:
[tex]\[2 \times \text{(missing denominator)} = 70\][/tex]
To find the missing denominator, divide both sides by 2:
[tex]\[\text{Missing denominator} = \frac{70}{2} = 35\][/tex]
So, [tex]\(\frac{2}{7} = \frac{10}{35}\)[/tex].
(c) [tex]\(\frac{\square}{5} = \frac{32}{40}\)[/tex]
Again, use cross-multiplication:
[tex]\[\text{(missing numerator)} \times 40 = 5 \times 32\][/tex]
This simplifies to:
[tex]\[\text{(missing numerator)} \times 40 = 160\][/tex]
To find the missing numerator, divide both sides by 40:
[tex]\[\text{Missing numerator} = \frac{160}{40} = 4\][/tex]
So, [tex]\(\frac{4}{5} = \frac{32}{40}\)[/tex].
In summary:
- For part (a), the missing number is 15.
- For part (b), the missing denominator is 35.
- For part (c), the missing numerator is 4.
