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------------------------------------------------ Factor the polynomial [tex]f(x)[/tex]. Then solve the equation [tex]f(x) = 0[/tex].

[tex]f(x) = x^4 - x^3 - 39x^2 + 109x - 70[/tex]

Answer :

To factor the polynomial [tex]\( f(x) = x^4 - x^3 - 39x^2 + 109x - 70 \)[/tex] and solve the equation [tex]\( f(x) = 0 \)[/tex], follow these steps:

### Step 1: Factor the Polynomial
The polynomial can be factored into simpler expressions, specifically into its linear factors. The given polynomial factors into:

[tex]\[ f(x) = (x - 5)(x - 2)(x - 1)(x + 7) \][/tex]

This means that the polynomial can be expressed as a product of these linear terms.

### Step 2: Solve the Equation [tex]\( f(x) = 0 \)[/tex]
To solve the equation [tex]\( f(x) = 0 \)[/tex], we set each factor equal to zero and solve for [tex]\( x \)[/tex]:

1. [tex]\( x - 5 = 0 \)[/tex]
[tex]\[ x = 5 \][/tex]

2. [tex]\( x - 2 = 0 \)[/tex]
[tex]\[ x = 2 \][/tex]

3. [tex]\( x - 1 = 0 \)[/tex]
[tex]\[ x = 1 \][/tex]

4. [tex]\( x + 7 = 0 \)[/tex]
[tex]\[ x = -7 \][/tex]

These steps show us that the solutions to the equation [tex]\( f(x) = 0 \)[/tex] are [tex]\( x = -7, 1, 2, \)[/tex] and [tex]\( 5 \)[/tex].

### Final Answer
So, the polynomial [tex]\( f(x) = x^4 - x^3 - 39x^2 + 109x - 70 \)[/tex] factors into [tex]\((x - 5)(x - 2)(x - 1)(x + 7)\)[/tex], and the solutions to the equation [tex]\( f(x) = 0 \)[/tex] are [tex]\( x = -7, 1, 2, \)[/tex] and [tex]\( 5 \)[/tex].