Answer :
To factor the polynomial [tex]\(10x^3 - 25x^2 - 2x + 5\)[/tex] by grouping, we can follow these steps:
1. Group the terms: We want to rearrange and group the terms such that we can factor out a common factor from each group. The polynomial is:
[tex]\[
10x^3 - 25x^2 - 2x + 5
\][/tex]
Let's group it as follows:
[tex]\[
(10x^3 - 25x^2) + (-2x + 5)
\][/tex]
2. Factor out the common factor from each group:
- From the first group [tex]\(10x^3 - 25x^2\)[/tex], we can factor out [tex]\(5x^2\)[/tex]:
[tex]\[
5x^2(2x - 5)
\][/tex]
- From the second group [tex]\(-2x + 5\)[/tex], we factor out [tex]\(-1\)[/tex]:
[tex]\[
-1(2x - 5)
\][/tex]
3. Combine the factored groups: Now, notice that both groups have a common factor of [tex]\((2x - 5)\)[/tex]. We can combine the groups as follows:
[tex]\[
5x^2(2x - 5) - 1(2x - 5)
\][/tex]
This becomes:
[tex]\[
(5x^2 - 1)(2x - 5)
\][/tex]
So, the polynomial [tex]\(10x^3 - 25x^2 - 2x + 5\)[/tex] is factored as:
[tex]\[
(5x^2 - 1)(2x - 5)
\][/tex]
And that is the factorization of the given polynomial by grouping.
1. Group the terms: We want to rearrange and group the terms such that we can factor out a common factor from each group. The polynomial is:
[tex]\[
10x^3 - 25x^2 - 2x + 5
\][/tex]
Let's group it as follows:
[tex]\[
(10x^3 - 25x^2) + (-2x + 5)
\][/tex]
2. Factor out the common factor from each group:
- From the first group [tex]\(10x^3 - 25x^2\)[/tex], we can factor out [tex]\(5x^2\)[/tex]:
[tex]\[
5x^2(2x - 5)
\][/tex]
- From the second group [tex]\(-2x + 5\)[/tex], we factor out [tex]\(-1\)[/tex]:
[tex]\[
-1(2x - 5)
\][/tex]
3. Combine the factored groups: Now, notice that both groups have a common factor of [tex]\((2x - 5)\)[/tex]. We can combine the groups as follows:
[tex]\[
5x^2(2x - 5) - 1(2x - 5)
\][/tex]
This becomes:
[tex]\[
(5x^2 - 1)(2x - 5)
\][/tex]
So, the polynomial [tex]\(10x^3 - 25x^2 - 2x + 5\)[/tex] is factored as:
[tex]\[
(5x^2 - 1)(2x - 5)
\][/tex]
And that is the factorization of the given polynomial by grouping.