Answer :
Solar Power can produce a total of 19,200 panels in 2 quarters.
Due to power failure and maintenance, Solar Power will lose 1,600 panels.
After considering the losses, Solar Power will have 17,600 panels available for a week.
To calculate the total panels produced in 2 quarters, we need to consider the production capacity per hour, the number of machines, and the working schedule. Each machine produces 100 cells per hour, and there are 10 machines. In a day, there are 3 shifts with 6 technicians each, resulting in 18 working hours (24 hours - 75 minutes break). Therefore, the daily production is
100×10×18=18,000
100×10×18=18,000 cells. Considering 5 working days per week and 4 weeks per month, the total production in 2 quarters is
18,000×5×4×2=19,200
18,000×5×4×2=19,200 panels.
On day 2, there was a power failure from 3:05 pm to 6:25 pm, resulting in a loss of production for that day. Since each machine produces 100 cells per hour, and there are 10 machines, the loss is
100×10×(6.25−3.05)=2,400
100×10×(6.25−3.05)=2,400 cells for that day. Additionally, from days 2-4, 4 solar tabber machines were pulled out for maintenance. This results in a loss of
100×4×18=7,200
100×4×18=7,200 cells. Therefore, the total loss of panels is
2,400+7,200=9,600
2,400+7,200=9,600 panels.
After considering the losses, the available panels for a week can be calculated. From the total production in a week, we subtract the lost panels (9,600) to obtain the available panels. The weekly production is
18,000×5=90,000
18,000×5=90,000 cells, which equals 450 panels. Thus, the available panels for a week are
450−9,600=17,600
450−9,600=17,600 panels.
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