College

Even with instruction reordering and forwarding, which one of the following codes must have a NOP inserted?

A.
- `slli x11, x11, 3`
- `add x11, x10, 11`
- `ld x5, 0(x11)`
- `addi x5, x5, 1`

B.
- `addi x5, x0, 13`
- `addi x6, x0, 7`
- `sub x5, x5, x6`
- `or x6, x6, x11`

C.
- `addi x10, x10, 8`
- `add x7, x5, x6`
- `ld x5, 0(x10)`
- `ld x6, 8(x10)`

D.
- `ld x5, 0(x10)`
- `ld x6, 0(x10)`
- `add x7, x5, x6`
- `addi x10, x10, 8`

Answer :

Final answer:

A NOP must be inserted in the code sequence 'Id x5, 0(x10) Id x6, 0(x10) add x7, X5, X6 addi x10, x10,8' to avoid a data hazard.

Explanation:

The student's question involves understanding when a No-Operation (NOP) may need to be inserted in a sequence of assembly language instructions to avoid hazards that cannot be resolved through instruction reordering or forwarding. Out of the given code snippets, we're looking for instances where a subsequent instruction requires a result from a previous instruction that is not yet available.

The sequence that requires a NOP is: Id x5, 0(x10) Id x6, 0(x10) add x7, X5, X6 addi x10, x10,8. Here, x7 depends on the values loaded into x5 and x6. However, the loads may not complete before the add instruction is executed, leading to a data hazard.

To resolve this, a NOP can be inserted between the load and add instructions, giving enough time for the load operations to complete before their results are required by the add instruction.