Answer :
The moment of inertia (I) of a bicycle wheel can be 0.124 kg*[tex]m^{2}[/tex]
The moment of inertia (I) of a bicycle wheel can be estimated using the equation for a thin hoop or ring:
I = M * [tex]R^{2}[/tex]
where M is the mass of the rim and tire, and R is the radius of the wheel.
Given the diameter of the wheel is 67 cm, the radius (R) is 67/2 = 33.5 cm, which is equivalent to 0.335 m. The combined mass (M) of the rim and tire is 1.1 kg.
Now, we can estimate the moment of inertia: I = 1.1 kg * [tex](0.335 m)^{2}[/tex] ≈ 0.124 kg*[tex]m^{2}[/tex].
The mass of the hub can be ignored because it's at the center and doesn't contribute significantly to the overall moment of inertia. The further away an object's mass is from the axis of rotation, the more it contributes to the moment of inertia.
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