Dogs were trained to be patient when waiting for a treat. In one population, the mean patience score was 100 seconds. A subgroup of this parental population that showed a higher patience score (mean = 150 seconds) was interbred, and their progeny were examined. These dogs demonstrated a mean patience score of 110 seconds.

What is the narrow-sense heritability (h) for this trait?

A. 0.5
B. 110/150
C. 100/150
D. 0.67
E. 0.2

The narrow-sense heritability (h^2) for the trait in question is calculated by dividing the Response to selection (change in progeny's mean trait value) by the Selection differential (difference in trait value between selected parents and initial population). In this scenario, both values are calculated and the equation provides a result of 0.2. Hence, the heritability of the trait is 0.2.

Explanation:

The subject at hand is a challenge to determine the narrow-sense heritability of a trait within a population of dogs, specifically related to patience. Heritability in the narrow sense (h^2) is given by the formula: h^2 = (Response to selection)/(Selection differential), where the 'Response to selection' refers to the change in the progeny's mean trait value compared to the initial population, and 'Selection differential' is the difference in trait value between the selected parents and the initial population. In this example, the 'Response to selection' is 110 - 100 = 10, and 'Selection differential' is 150 - 100 = 50. Therefore, applying the formula, h^2 is 10/50 = 0.2. So, the narrow-sense heritability for this trait is 0.2.

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