High School

Divide using partial quotients:

1. [tex]36 \div 540[/tex]

2. [tex]27 \div 624[/tex]

3. [tex]478 \div 16[/tex]

4. [tex]625 \div 25[/tex]

5. [tex]322 \div 14[/tex]

Answer :

Final answer:

Using the partial quotients method, the solution for 540/36 is 15, for 624/27 it’s 23 with a remainder of 3, for 478/16 it’s 29 with a remainder of 14, for 625/25 it’s 25, and for 322/14, it’s 23 with no remainder.

Explanation:

When you use the partial quotients method, also known as the chunking method, you divide in pieces. Here are the solutions to the problems you've mentioned:

  1. Divide 540 by 36: Place 540 under a division bar and place 36 to the left outside the bar. Next, think: How many times does 36 go into 540 approximately (without exceeding 540)? Let's say, 10 times. Write 10 above the bar, and subtract 360 (10*36) from 540 to get 180. Then, think: How many times does 36 go into 180? The answer is 5. Write down 5 next to the 10 above the bar and subtract 180 from 180 to get 0. Your answer is therefore 15 (10 + 5).
  2. Divide 624 by 27: Use the same method as above. The answer is 23 with a remainder of 3.
  3. Divide 478 by 16: The answer is 29 plus a remainder of 14.
  4. Divide 625 by 25: The answer is 25.
  5. Divide 322 by 14: The answer is 23 with a remainder of 0.

Learn more about Partial Quotients here:

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