Answer :
To divide
[tex]$$\frac{36x^5 - 60x^3 + 24x^2}{6x^2},$$[/tex]
we can divide each term in the numerator by the denominator.
1. For the first term:
[tex]$$\frac{36x^5}{6x^2} = 6x^{5-2} = 6x^3.$$[/tex]
2. For the second term:
[tex]$$\frac{-60x^3}{6x^2} = -10x^{3-2} = -10x.$$[/tex]
3. For the third term:
[tex]$$\frac{24x^2}{6x^2} = 4.$$[/tex]
Now, combine all three results to obtain the simplified expression:
[tex]$$6x^3 - 10x + 4.$$[/tex]
[tex]$$\frac{36x^5 - 60x^3 + 24x^2}{6x^2},$$[/tex]
we can divide each term in the numerator by the denominator.
1. For the first term:
[tex]$$\frac{36x^5}{6x^2} = 6x^{5-2} = 6x^3.$$[/tex]
2. For the second term:
[tex]$$\frac{-60x^3}{6x^2} = -10x^{3-2} = -10x.$$[/tex]
3. For the third term:
[tex]$$\frac{24x^2}{6x^2} = 4.$$[/tex]
Now, combine all three results to obtain the simplified expression:
[tex]$$6x^3 - 10x + 4.$$[/tex]
