Determine the outside dimensions of a house given the following details:

- Interior walls consist of a 2x4 (3-1/2") structure with 1/2" drywall on both sides.
- Exterior walls are constructed with 2x6 (5-1/2") framing, 1/2" drywall on the interior, and 7/16" sheeting with 3-5/8" brick on the exterior.

There are two interior rooms separated by an interior wall:
- Room 1 dimensions: 11' 3"
- Room 2 dimensions: 15' 7"

To determine the outside dimension of the house, we add the total thickness of the exterior walls to the dimensions of the interior rooms. The outside dimension is 42.945 feet.

Explanation:

To determine the outside dimension of the house, we need to calculate the total thickness of the exterior walls and add it to the dimensions of the interior rooms. The exterior walls consist of a 2x6 construction with 1/2" drywall on the interior and 7/16" sheeting with 3-5/8" brick on the exterior. This adds up to a total thickness of 5-1/2" + 1/2" + 7/16" + 3-5/8" = 9-11/16".

For Room 1, with a dimension of 11' 3" (or 11.25 feet), we add twice the thickness of the interior walls: 11.25 + 2 * 3.5 = 18.25 feet.

Similarly, for Room 2 with a dimension of 15' 7" (or 15.58 feet), we add twice the thickness of the interior walls: 15.58 + 2 * 3.5 = 22.58 feet.

Finally, we add the total thickness of the exterior walls to the maximum dimension of the rooms to get the outside dimension of the house. In this case, the maximum dimension is Room 2, so the outside dimension is 22.58 + 2 * 9.6875 = 42.945 feet.