Determine the amount of standard gypsum lath in square feet for a building with 1,140 square feet of floor area and the number of bundles necessary. The total length of all inside wall surfaces is 362 feet, and the ceiling is 8 feet high. Make no allowances for doors and windows, and round your answer up to the nearest full bundle of lath.

a) Square feet:

b) Bundles of lath:

To cover a building with a floor area of a) 1140 sq. ft. and wall area calculated based on a total inside surface length of 362' and height of 8', 4036 sq. ft. of gypsum lath is needed, rounding up to b) 81 bundles for purchase.

Explanation:

To determine the amount of standard gypsum lath needed for a building with 1140 sq. ft. of floor area, we first calculate the area of the walls. The total length of all inside wall surfaces is 362', with a ceiling height of 8'. Therefore, the wall area is 362' × 8' = 2896 sq. ft. Adding the floor area (1140 sq. ft.) to this gives us a total area of 4036 sq. ft. that needs to be covered with gypsum lath.

Gypsum lath typically comes in bundles that cover 50 sq. ft. So, to find the number of bundles needed, we divide the total area by 50 sq. ft. per bundle, resulting in 80.72 bundles. Since we can't purchase a fraction of a bundle, we round up to the nearest full bundle, requiring 81 bundles of lath in total.