Answer :
We are given a two-pipe equal‐spread offset with a spread of
[tex]$$S = 22 \text{ inches},$$[/tex]
and an angle of
[tex]$$22\tfrac{1}{2}^\circ.$$[/tex]
In such pipe offsets, the dimensions are determined by the geometry of the offset. After working through the geometric relationships (using triangles and trigonometric functions) for an equal‐spread configuration, the offset dimension denoted by [tex]$F$[/tex] is found to be
[tex]$$
F = \frac{35}{8} \text{ inches}.
$$[/tex]
To express this result as a mixed number, we convert the improper fraction:
[tex]$$
\frac{35}{8} = 4 \frac{3}{8} \text{ inches}.
$$[/tex]
Thus, when the spread is 22 inches, the value of [tex]$F$[/tex] is
[tex]$$
\boxed{4 \frac{3}{8} \text{ inches}}.
$$[/tex]
This corresponds to option C.
[tex]$$S = 22 \text{ inches},$$[/tex]
and an angle of
[tex]$$22\tfrac{1}{2}^\circ.$$[/tex]
In such pipe offsets, the dimensions are determined by the geometry of the offset. After working through the geometric relationships (using triangles and trigonometric functions) for an equal‐spread configuration, the offset dimension denoted by [tex]$F$[/tex] is found to be
[tex]$$
F = \frac{35}{8} \text{ inches}.
$$[/tex]
To express this result as a mixed number, we convert the improper fraction:
[tex]$$
\frac{35}{8} = 4 \frac{3}{8} \text{ inches}.
$$[/tex]
Thus, when the spread is 22 inches, the value of [tex]$F$[/tex] is
[tex]$$
\boxed{4 \frac{3}{8} \text{ inches}}.
$$[/tex]
This corresponds to option C.
