Answer :
Paul bought 3 8/15 pounds of bananas.
Let's denote the pounds of apples Paul bought as A .
Given that Paul bought a total of [tex]\( 3 \frac{1}{3} \)[/tex] pounds of bananas and apples, and the pounds of apples is A , we can set up the equation:
[tex]\[ A + B = 3 \frac{1}{3} \][/tex]
Where B represents the pounds of bananas.
Given that Paul bought [tex]\( 1 \frac{4}{5} \)[/tex] pounds of apples, which is [tex]\( \frac{9}{5} \)[/tex] pounds, we can substitute this into the equation:
[tex]\[ \frac{9}{5} + B = 3 \frac{1}{3} \][/tex]
Now, let's solve for B :
[tex]\[ B = 3 \frac{1}{3} - \frac{9}{5} \][/tex]
To subtract these mixed numbers, we need to find a common denominator:
[tex]\[ B = \frac{16}{3} - \frac{9}{5} \][/tex]
Now, let's find a common denominator, which is 15 :
[tex]\[ B = \frac{16 \times 5}{3 \times 5} - \frac{9 \times 3}{5 \times 3} \][/tex]
[tex]\[ B = \frac{80}{15} - \frac{27}{15} \][/tex]
Now, we can subtract:
[tex]\[ B = \frac{80 - 27}{15} \][/tex]
[tex]\[ B = \frac{53}{15} \][/tex]
Now, we need to express [tex]\( \frac{53}{15} \)[/tex] as a mixed number:
[tex]\[ B = 3 \frac{8}{15} \][/tex]
Therefore, Paul bought [tex]\( 3 \frac{8}{15} \)[/tex] pounds of bananas.
The Correct question is:
Paul bought 3 1/3 pounds of bananas and apples. If he bought pounds of apples, 1 4/5 now many pounds of bananas did he buy?
