Answer :
First, we need to determine the total volume of limestone required by including a 7% waste allowance. The original job requires [tex]$120$[/tex] cubic feet. To include the waste, we calculate:
[tex]$$
\text{Total volume} = 120 \times (1 + 0.07) = 120 \times 1.07 = 128.4 \text{ cubic feet}.
$$[/tex]
Next, knowing that construction limestone weighs approximately [tex]$165$[/tex] pounds per cubic foot, we can calculate the total weight needed by multiplying the volume (including waste) by the weight per cubic foot:
[tex]$$
\text{Total weight} = 128.4 \times 165 = 21186 \text{ pounds}.
$$[/tex]
So, for a job requiring [tex]$120$[/tex] cubic feet of limestone with a 7% waste allowance, a total of [tex]$21186$[/tex] pounds of limestone is needed.
[tex]$$
\text{Total volume} = 120 \times (1 + 0.07) = 120 \times 1.07 = 128.4 \text{ cubic feet}.
$$[/tex]
Next, knowing that construction limestone weighs approximately [tex]$165$[/tex] pounds per cubic foot, we can calculate the total weight needed by multiplying the volume (including waste) by the weight per cubic foot:
[tex]$$
\text{Total weight} = 128.4 \times 165 = 21186 \text{ pounds}.
$$[/tex]
So, for a job requiring [tex]$120$[/tex] cubic feet of limestone with a 7% waste allowance, a total of [tex]$21186$[/tex] pounds of limestone is needed.
