Answer :
To solve the given problem, we need to understand the type of nuclear reaction presented. The reaction involves an isotope of Bismuth ([tex]\(_{83}^{210}Bi\)[/tex]) and a beta particle ([tex]\(_{-1}^0e\)[/tex]).
The reaction described here is a beta decay. In beta decay:
1. A neutron in the nucleus of the atom is converted to a proton.
2. This process emits a beta particle, which is an electron ([tex]\(_{-1}^0e\)[/tex]), from the nucleus.
As a result of the neutron being converted into a proton, the atomic number of the element increases by 1 while the mass number remains the same.
Let's break this down using the information provided:
- Original Nuclide: [tex]\(_{83}^{210}Bi\)[/tex]
- Atomic number (Z): 83
- Mass number (A): 210
- Daughter Nuclide after Beta Decay:
- New Atomic Number (Z): 83 + 1 = 84
- Mass Number (A): 210 (unchanged)
Now, using the periodic table:
- The element with atomic number 84 is Polonium (Po).
Therefore, after the beta decay, the daughter nuclide formed is [tex]\(_{84}^{210}Po\)[/tex], which is Po-210.
The reaction described here is a beta decay. In beta decay:
1. A neutron in the nucleus of the atom is converted to a proton.
2. This process emits a beta particle, which is an electron ([tex]\(_{-1}^0e\)[/tex]), from the nucleus.
As a result of the neutron being converted into a proton, the atomic number of the element increases by 1 while the mass number remains the same.
Let's break this down using the information provided:
- Original Nuclide: [tex]\(_{83}^{210}Bi\)[/tex]
- Atomic number (Z): 83
- Mass number (A): 210
- Daughter Nuclide after Beta Decay:
- New Atomic Number (Z): 83 + 1 = 84
- Mass Number (A): 210 (unchanged)
Now, using the periodic table:
- The element with atomic number 84 is Polonium (Po).
Therefore, after the beta decay, the daughter nuclide formed is [tex]\(_{84}^{210}Po\)[/tex], which is Po-210.
