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Consider the reaction.


A(aq)↽−−⇀2B(aq)=4.87×10−6 at 500 K


If a 2.00 M sample of A is heated to 500 K, what is the concentration of B at equilibrium?

Consider the reaction A aq 2B aq 4 87 10 6 at 500 K If a 2 00 M sample of A is heated to

Answer :

The equilibrium constant K is the ratio of product of molar concentrations of products to the product of molar concentrations of reactants. The concentration of B in the given reaction is 0.0031 M.

What is rate of a reaction?

Rate of a reaction is the rate of decrease in the concentration of the reactants or rate of increase in the concentration of products.

Consider the simple reaction A ⇄2B, the rate of the reaction can be written as follows:

rate = K [A]

Where, k is the equilibrium constant or rate constant and [A] is the concentration of reactant A. If A have any coefficients, then the coefficient number is written as power of the concentration term.

The equilibrium constant K = [B]²/ [A] it is given 4.87 ×10⁻⁶ . Thus concentration of B can be calculated as follows:

[B]² = K [A]

= (4.87 ×10⁻⁶)×2.00 M

=9×10⁻⁶

[B] = 0.0031 M

Hence, the concentration of the product B is 0.0031 M.

To learn more about rate of reaction, refer the link below:

https://brainly.com/question/8592296

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