High School

Consider the equilibrium system described by the chemical reaction below. For this reaction, [tex]K_p = 4.51 \times 10[/tex] at a particular temperature. Calculate the value of [tex]Q_p[/tex] for the initial set reaction conditions: 57 atm [tex]NH_3[/tex], 27 atm [tex]N_2[/tex], 82 atm [tex]H_2[/tex].

Based on the given data, set up the expression for [tex]Q_p[/tex] and then evaluate it. Do not combine or simplify terms.

[tex]Q_p = \, \_\_\_\_\_\_\_\_\_\_\_\_[/tex]

Answer :

Final answer:

The value of Qp for the initial reaction conditions is 1.90 x 10^-6.

Explanation:

To calculate the value of Qp for the given initial set reaction conditions, we need to set up the expression for Qp using the partial pressures of the reactants and products. The chemical equation for the reaction is N₂ + 3H₂ ⇌ 2NH₃. Using the given initial pressures of 57 atm NH₃, 27 atm N₂, and 82 atm H₂, the expression for Qp is:

Qp = (P(NH₃))² / (P(N₂) * P(H₂)³)

Substituting the given values:

Qp = (57)² / (27 * 82³) = 1.90 x 10-6

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