Consider the array \( a = \langle 3, 60, 25, 15, 10, 30, 6, 50, 90, 70 \rangle \).

After calling the function `build-max-heap(a)`, what is the updated array \( a \)?

a) \( \langle 90, 70, 25, 60, 10, 30, 6, 50, 15, 3 \rangle \)

b) \( \langle 90, 70, 30, 60, 10, 25, 6, 50, 15, 3 \rangle \)

c) \( \langle 90, 70, 30, 60, 15, 25, 6, 50, 10, 3 \rangle \)

d) \( \langle 90, 70, 30, 60, 15, 25, 6, 50, 10, 3 \rangle \)

The function build-max-heap(a) is used to build a max heap from an array. The updated array after calling the function is <90, 70, 30, 60, 15, 25, 6, 50, 10, 3>.

Explanation:

The function build-max-heap(a) is used to build a max heap from an array. In a max heap, the value of each parent node is greater than or equal to the values of its children. To build a max heap, we start from the last non-leaf node and move up the tree. For the given array a = <3, 60, 25, 15, 10, 30, 6, 50, 90, 70>, the updated array after calling the function build-max-heap(a) is <90, 70, 30, 60, 15, 25, 6, 50, 10, 3>. So, the correct answer is d) <90, 70, 30, 60, 15, 25, 6, 50, 10, 3>.