Answer :
To calculate the heat energy absorbed by the water, we can use the formula:
Q = mcΔT
Where Q is the heat energy absorbed, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
First, we need to calculate the mass of the water in the top 1 cm of the area:
Volume of top 1 cm of water = 1 cm x 100 km x 100 km = 1 x 10⁸ m³
Density of water = 1000 kg/m³
Mass of water = Volume x Density = 1 x 10⁸ m x 1000 kg/m³ = 1 x 10¹¹ kg
Next, we can calculate the heat energy absorbed using the specific heat capacity of water (4.184 J/g°C):
ΔT = 27°C - 25°C = 2°C
Q = (1 x 10¹¹ kg) x (4.184 J/g°C) x (2°C) = 8.368 x 10¹¹ J
Therefore, the water in the top 1 cm of the 100 km by 100 km area has absorbed approximately 8.368 x 10¹¹ joules of heat energy.
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