Consider a population of 100 Hampshire swine where the [tex]W[/tex] allele for a white belt is completely dominant to the [tex]w[/tex] allele for solid color. Assume that the population of Hampshire swine is in Hardy-Weinberg equilibrium for the [tex]W[/tex] and [tex]w[/tex] alleles. In this population, 75 of the swine are belted and 25 are solid colored. We do not know how many of the 75 belted swine are [tex]WW[/tex] and how many are [tex]Ww[/tex] due to the existence of complete dominance at the [tex]W[/tex] locus.

Find the frequencies of the [tex]W[/tex] and [tex]w[/tex] alleles. Then, find the expected number of [tex]WW[/tex], [tex]Ww[/tex], and [tex]ww[/tex] swine given that this population is in Hardy-Weinberg equilibrium.

We can calculate the values of p and q, in a representative sample of individuals from a population, by simply counting the alleles and dividing by the total number of alleles examined.

By simply counting the alleles and dividing by the total number of alleles analysed, we may get the values of p and q in a representative sample of people from a community. Homozygotes represent twice as many of an allele as heterozygotes. the prevalence of the allele "a". Answer: Aa occurs 36% of the time, hence q2 must equal 0.36 by definition. Again, by definition, q = 0.6 if q2 = 0.36. The frequency is 60% because q equals the frequency of the an allele. p 2 + 2 p q + q 2 = 1 p 2 + 2 p q + q 2 = 1 p 2 + 2 p q + q 2 = 1 is the Hardy-Weinberg equation, which is used to calculate the frequency of genotypes in a population.

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