Answer :
For a fiber with an index of refraction of 1.55 over a distance of 0.200 m, the time required is approximately 1.034 nanoseconds.
To determine this, we need to use the speed of light in an optical fiber. The speed of light in a medium is given by: v = c / n, where c is the speed of light in a vacuum (~299,792,458 m/s) and n is the index of refraction.
Given: n = 1.55
Thus, the speed of light in the fiber:
v = 299,792,458 m/s / 1.55 ≈ 193,415,780.65 m/s
Now, we use the formula: time = distance/speed
Given distance: d = 0.200 m
Thus:
time = 0.200 m / 193,415,780.65 m/s ≈ 1.034 × [tex]10^{9}[/tex] seconds
Since 1 second = [tex]10^{9}[/tex] nanoseconds, the time required is approximately 1.034 nanoseconds.
