Answer :
Answer:
The steps are shown below. From here, we can write:
[tex]\frac{x^3-2x^2-14x+3}{x+3}=x^2-5x+1+\frac{0}{x+3} \\ \\ \therefore \boxed{\frac{x^3-2x^2-14x+3}{x+3}=x^2-5x+1}[/tex]
The steps are shown below. From here, we can write:
[tex]\frac{x^3-2x^2-14x+3}{x+3}=x^2-5x+1+\frac{0}{x+3} \\ \\ \therefore \boxed{\frac{x^3-2x^2-14x+3}{x+3}=x^2-5x+1}[/tex]
