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Cesium-137 is part of the nuclear waste produced by uranium-235 fission. The half-life of cesium-137 is 30.2 years. How much time is required for the activity of a sample of cesium-137 to fall to 13.3 percent of its original value?

Answer :

Final answer:

To determine the time required for the activity of cesium-137 to fall to 13.3 percent of its original value, we can use the concept of half-life.

Explanation:

To determine how much time is required for the activity of a sample of cesium-137 to fall to 13.3 percent of its original value, we can use the concept of half-life.

The half-life of cesium-137 is 30.2 years, which means that after each half-life period, the activity of the sample is reduced by half.

We can use the formula N = N0 * (1/2)(t/T), where N is the current activity, N0 is the original activity, t is the time passed, and T is the half-life.

By substituting the values into the formula, we can solve for t and find the required time.

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