Answer :
To factor the polynomial [tex]\(16x^6 - 9\)[/tex] using the steps Cecile outlined, let's walk through the process step by step:
### Step 1: Recognize the form
The expression [tex]\(16x^6 - 9\)[/tex] is a difference of squares. We can write it as:
[tex]\[
(4x^3)^2 - 3^2
\][/tex]
### Step 2: Apply the Difference of Squares Formula
The difference of squares formula is:
[tex]\[
a^2 - b^2 = (a + b)(a - b)
\][/tex]
In this case, [tex]\(a = 4x^3\)[/tex] and [tex]\(b = 3\)[/tex].
### Step 3: Substitute and Factor
Using the formula, we get:
[tex]\[
(4x^3)^2 - 3^2 = (4x^3 + 3)(4x^3 - 3)
\][/tex]
### Conclusion
The factored form of the polynomial [tex]\(16x^6 - 9\)[/tex] is:
[tex]\[
(4x^3 + 3)(4x^3 - 3)
\][/tex]
This is the final answer in its factored form.
### Step 1: Recognize the form
The expression [tex]\(16x^6 - 9\)[/tex] is a difference of squares. We can write it as:
[tex]\[
(4x^3)^2 - 3^2
\][/tex]
### Step 2: Apply the Difference of Squares Formula
The difference of squares formula is:
[tex]\[
a^2 - b^2 = (a + b)(a - b)
\][/tex]
In this case, [tex]\(a = 4x^3\)[/tex] and [tex]\(b = 3\)[/tex].
### Step 3: Substitute and Factor
Using the formula, we get:
[tex]\[
(4x^3)^2 - 3^2 = (4x^3 + 3)(4x^3 - 3)
\][/tex]
### Conclusion
The factored form of the polynomial [tex]\(16x^6 - 9\)[/tex] is:
[tex]\[
(4x^3 + 3)(4x^3 - 3)
\][/tex]
This is the final answer in its factored form.