High School

Castel and Gabriella are selling pies for a school fundraiser. Customers can buy apple pies and lemon meringue pies.

Castel sold 6 apple pies and 4 lemon meringue pies for a total of $80.

Gabriella sold 6 apple pies and 5 lemon meringue pies for a total of $94.

What is the cost of one apple pie and one lemon meringue pie?

Answer :

Final answer:

To solve this question, we can set up a system of two equations based off the number and type of pies sold and total amount of money made. After solving the system, we find that the cost of an apple pie is $8 and the cost of a lemon meringue pie is $14.

Explanation:

Let's consider the cost of an apple pie as x and the cost of a lemon meringue pie as y.

The sequence of sales for Castel can be denoted by the equation: 6x + 4y = $80

For Gabriella, the sales can be represented as: 6x + 5y = $94

To solve this system of two equations, we can use the method of substitution, elimination, or matrix. If we use the elimination method, we can subtract the first equation from the second which gives: y = $14

Substituting y back into the first equation gives x = $8

Therefore, an apple pie costs $8 and a lemon meringue pie costs $14.

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The cost of one apple pie is $10 and the cost of one lemon meringue pie is $12.

The cost of one apple pie is $10 and the cost of one lemon meringue pie is $12.

To find the cost of one apple pie and one lemon meringue pie, you can set up a system of equations using the given information:

Let x be the cost of one apple pie and y be the cost of one lemon meringue pie.

From Castel's sales: 6x + 4y = 80.

From Gabriella's sales: 6x + 5y = 94.

Solving the system of equations, we get x = 10 and y = 12.