Answer :
To calculate the z-score for someone with an IQ of 96 in Group A, we first need to find the deviation of this IQ score from the average IQ of the group, Deviation = 96 - 120 = -24 .
Next, we need to standardize this deviation by dividing it by the standard deviation of the group: z-score = (-24) / 15 = -1.6
Therefore, the z-score for someone with an IQ of 96 in Group A is -1.6. This tells us that this IQ score is 1.6 standard deviations below the average IQ of the group.
To calculate the z-score for someone with an IQ of 96 in Group A, you will need to use the average IQ and standard deviation you've provided. The formula for the z-score is: Z-score = (Individual IQ - Average IQ) / Standard Deviation
In this case: Z-score = (96 - 120) / 15, Z-score = -24 / 15, Z-score = -1.6
The z-score for someone with an IQ of 96 in Group A is -1.6.
To know more about formula click here
brainly.com/question/30098455
#SPJ11
