Answer :
To calculate the wavelength [tex]\lambda_2[/tex] for visible light with a given frequency [tex]f_2 = 6.00 \times 10^{14}[/tex] Hz, we can use the formula relating the speed of light [tex]c[/tex], frequency [tex]f[/tex], and wavelength [tex]\lambda[/tex]:
[tex]\lambda = \frac{c}{f}[/tex]
Here, [tex]c[/tex] is the speed of light in a vacuum, which is approximately [tex]3.00 \times 10^8[/tex] meters per second (m/s).
Step-by-step calculation:
Substitute the known values into the formula:
[tex]\lambda_2 = \frac{3.00 \times 10^8 \text{ m/s}}{6.00 \times 10^{14} \text{ Hz}}[/tex]Perform the division:
[tex]\lambda_2 = 5.00 \times 10^{-7} \text{ meters}[/tex]This is equivalent to 500 nanometers (nm), since 1 meter equals 1 billion nanometers (1 m = 10^9 nm).
Therefore, the wavelength [tex]\lambda_2[/tex] of the visible light with a frequency [tex]f_2 = 6.00 \times 10^{14}[/tex] Hz is 500 nm, which falls in the middle of the visible light spectrum. This frequency corresponds to green light.
