Answer :
To determine the wavelength of the radio waves, we start with the basic relationship between the speed of light, wavelength, and frequency:
[tex]$$
c = \lambda \times f
$$[/tex]
Here,
- [tex]$c$[/tex] is the speed of light (approximately [tex]$3 \times 10^8 \; \text{m/s}$[/tex]),
- [tex]$f$[/tex] is the frequency, and
- [tex]$\lambda$[/tex] is the wavelength.
Given that the frequency is
[tex]$$
f = 99.7 \times 10^6 \; \text{Hz},
$$[/tex]
we can rearrange the formula to solve for the wavelength [tex]$\lambda$[/tex]:
[tex]$$
\lambda = \frac{c}{f}.
$$[/tex]
Substituting the known values:
[tex]$$
\lambda = \frac{3 \times 10^8 \; \text{m/s}}{99.7 \times 10^6 \; \text{Hz}}.
$$[/tex]
When you perform the division, you get:
[tex]$$
\lambda \approx 3.009 \; \text{m}.
$$[/tex]
Thus, the wavelength of the twin arty radio waves is approximately [tex]$3.009$[/tex] meters.
[tex]$$
c = \lambda \times f
$$[/tex]
Here,
- [tex]$c$[/tex] is the speed of light (approximately [tex]$3 \times 10^8 \; \text{m/s}$[/tex]),
- [tex]$f$[/tex] is the frequency, and
- [tex]$\lambda$[/tex] is the wavelength.
Given that the frequency is
[tex]$$
f = 99.7 \times 10^6 \; \text{Hz},
$$[/tex]
we can rearrange the formula to solve for the wavelength [tex]$\lambda$[/tex]:
[tex]$$
\lambda = \frac{c}{f}.
$$[/tex]
Substituting the known values:
[tex]$$
\lambda = \frac{3 \times 10^8 \; \text{m/s}}{99.7 \times 10^6 \; \text{Hz}}.
$$[/tex]
When you perform the division, you get:
[tex]$$
\lambda \approx 3.009 \; \text{m}.
$$[/tex]
Thus, the wavelength of the twin arty radio waves is approximately [tex]$3.009$[/tex] meters.
