Answer :
To calculate the volume of oxygen consumed in 1 hour by the average man, we can use the following steps:after the weight loss and increased Vo,max, the man would consume approximately 320,180.678 ml of oxygen in 1 hour.
Step 1: Convert the weight of the man from pounds to kilograms.
182 lbs * 0.4536 kg/lb = 82.5532 kg
Step 2: Calculate the oxygen consumption rate in ml O2/kg body mass/min.
47.5 mL O2/kg body mass/min
Step 3: Convert the oxygen consumption rate to ml O2/hr.
47.5 mL O2/kg body mass/min * 60 min/hr = 2850 mL O2/kg body mass/hr
Step 4: Calculate the volume of oxygen consumed by the man in 1 hour.
2850 mL O2/kg body mass/hr * 82.5532 kg = 235277.526 mL O2/hr
Therefore, the average man would consume approximately 235,277.526 ml of oxygen in 1 hour.
To calculate the volume of oxygen consumed after the weight loss and increased Vo,max, we can use the same steps with the updated Vo,max value of 64.8 mL O2/kg body mass/min.
Step 1: Calculate the oxygen consumption rate in ml O2/hr.
64.8 mL O2/kg body mass/min * 60 min/hr = 3888 mL O2/kg body mass/hr
Step 2: Calculate the volume of oxygen consumed in 1 hour.
3888 mL O2/kg body mass/hr * 82.5532 kg = 320180.678 ml O2/hr
Therefore, after the weight loss and increased Vo,max, the man would consume approximately 320,180.678 ml of oxygen in 1 hour.
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