Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ Calculate the terminal voltage for a battery with an internal resistance of 2.19 Ω and an emf of 6.00 V when the battery is connected in series with a 150 Ω resistor.

A. 5.62 V
B. 4.75 V
C. 4.00 V
D. 6.00 V

The calculated terminal voltage of a battery with an emf of 6.00 volts and an internal resistance of 2.19 ohms, when connected in series with a 150 ohm resistor is 5.91 volts, which is not among the provided options.

Explanation:

The subject of this question is Physics, more specifically, the concept of terminal voltage within the context of electrical circuits. The terminal voltage of a battery can be calculated using the equation: V = E - Ir, where V is the terminal voltage, E is the electromotive force (emf) or the battery's nominal voltage, I is the current, and r is the internal resistance of the battery. In this case, the battery's emf (E) is 6.00 volts, the internal resistance (r) is 2.19 ohms. The total resistance in the circuit is the sum of the internal resistance and the resistance of the resistor connected in series, in this case, 150 ohms. Therefore, the current (I) can be calculated through Ohm's law: I = E / (r + R), where R is the resistance of the resistor, i.e., I = 6.00 / (2.19 + 150) = 0.0397 amps. Now we can substitute I and r into the equation for the terminal voltage: V = E - Ir, V = 6.00 - (0.0397 * 2.19) = 5.91 volts.

So none of the options provided (a)5.62 V b)4.75 V c)4.00 V d)6.00 V) match the calculated terminal voltage.

Learn more about Terminal Voltage here:

https://brainly.com/question/33716898

#SPJ11