High School

Calculate the specific heat capacity of a piece of wood if 1.5 kg of the wood absorbs 67,500 joules of heat, and its temperature changes from 32°C to 57°C.

Show your work.

Answer :

The specific heat capacity of the piece of wood is 1,800 J/(kg°C). This was calculated using the formula Q = mcΔT, with the provided values of heat absorbed, mass of the wood, and change in temperature.

The question involves calculating the specific heat capacity of a piece of wood. The specific heat capacity is the amount of heat per unit mass required to raise the temperature by one degree Celsius. To calculate this, we can use the formula

Q = mcΔT,

where Q is the heat absorbed, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Given that the piece of wood absorbs 67,500 joules of heat (Q) to change the temperature from 32°C to 57°C, we can find the change in temperature (ΔT) as

(57 - 32) = 25°C.

The mass (m) given is 1.5 kg.

Substituting these values into the formula, we can solve for c:

c = Q / (m * ΔT).

c = 67,500 J / (1.5 kg * 25°C)

= 67,500 J / (37.5 kg°C)

= 1,800 J/(kg°C).

Therefore, the specific heat capacity of the wood is 1,800 J/(kg°C).