Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ Calculate the sample standard deviation for the following data set. If necessary, round to one more decimal place than the largest number of decimal places given in the data.

[tex]\[
\begin{array}{|c|c|c|c|c|}
\hline
\multicolumn{5}{|c|}{\text{Body Temperatures (in °F)}} \\
\hline
98.1 & 98.0 & 98.4 & 97.2 & 99.2 \\
\hline
97.7 & 98.2 & 96.5 & 97.1 & 97.9 \\
\hline
96.6 & 97.8 & 97.8 & 99.2 & 97.0 \\
\hline
97.9 & 97.1 & 99.2 & 97.1 & 97.7 \\
\hline
\end{array}
\][/tex]

To calculate the sample standard deviation for the given data set of body temperatures, follow these steps:

### Step 1: List the Data
Here are the body temperatures provided:
- 98.1, 98.0, 98.4, 97.2, 99.2
- 97.7, 98.2, 96.5, 97.1, 97.9
- 96.6, 97.8, 97.8, 99.2, 97.0
- 97.9, 97.1, 99.2, 97.1, 97.7

### Step 2: Calculate the Mean
Add all the temperatures together and divide by the number of temperatures to find the mean.

[tex]\[
\text{Mean} = \frac{(98.1 + 98.0 + \ldots + 97.7)}{20} = 97.785
\][/tex]

### Step 3: Calculate the Deviations
Subtract the mean from each individual temperature to find the deviations.

[tex]\[
\text{Deviations: } (98.1 - 97.785), (98.0 - 97.785), \ldots, (97.7 - 97.785)
\][/tex]

### Step 4: Square the Deviations
Square each of the deviations obtained in the previous step.

### Step 5: Calculate the Sample Variance
Sum all the squared deviations and divide by the number of temperatures minus one (which is 20 - 1 = 19) to get the sample variance.

[tex]\[
\text{Sample Variance} = \frac{\sum (\text{Squared Deviations})}{19} = 0.6403
\][/tex]

### Step 6: Calculate the Sample Standard Deviation
Take the square root of the sample variance to find the sample standard deviation.

[tex]\[
\text{Sample Standard Deviation} = \sqrt{0.6403} = 0.8
\][/tex]

### Conclusion
Therefore, the sample standard deviation of the body temperatures is approximately 0.8 (rounded to one decimal place).