Answer :
Explanation:
As molarity is the number of moles present in liter of solution. So, convert given volume into liter as follows.
[tex]250 ml \times \frac{1 L}{1000 ml}[/tex] (as 1 L = 1000 ml)
= 0.25 L
Therefore, number of moles of solute present will be calculated as follows.
Molarity = [tex]\frac{\text{no. of moles}}{volume}[/tex]
6.00 M = [tex]\frac{\text{no. of moles}}{0.25 L}[/tex]
no. of moles = 1.5 mol
Hence, number of moles of solute in 250.0 ml of 6.00 M NaOH is 1.5 mol.
Now, calculate the mass of solute as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
1.5 mol = [tex]\frac{mass}{39.99 g/mol}[/tex]
mass = 59.98 g
Thus, we can conclude that mass of solute in 250.0 ml of 6.00 M NaOH is 59.98 g.
If it is 6.00 M (molar) NaOH, there are 6 moles per liter. Use this equation to find the amount of moles in 250 mL
Molarity x Liters = Moles
We have the molarity already (6.00 M), so we just need to convert mL to L.
250 mL x 1 Liter/1000 mL = .25 L
Set up the equation
6.00 M x .25 L = 1.5 moles
Molarity x Liters = Moles
We have the molarity already (6.00 M), so we just need to convert mL to L.
250 mL x 1 Liter/1000 mL = .25 L
Set up the equation
6.00 M x .25 L = 1.5 moles
